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30p^2+84p-18=0
a = 30; b = 84; c = -18;
Δ = b2-4ac
Δ = 842-4·30·(-18)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-96}{2*30}=\frac{-180}{60} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+96}{2*30}=\frac{12}{60} =1/5 $
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